Chemistry Help — How many Mo atoms are present in 3 formulas of the compound, molybdenum(III) phosphate?
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burpzalot862 asked:
How many Mo atoms are present in 3 formulas of the compound, molybdenum(III) phosphate?
How many Mo atoms are present in 3 formulas of the compound, molybdenum(III) phosphate?
Please explain how you found this answer. I really need to learn this..
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November 17th, 2008 at 1:11 am
The synthesis, single-crystal x-ray structural characterization, and sorption properties of a microporous molybdenum phosphate, (Me4N)1.3(H3O)0.7[Mo4O8(PO4)2] ยท 2H2O (Me, methyl), are presented. The three-dimensional framework is built up from Mo4O84+ cubes and PO43- tetrahedra that are connected in such a way that large, cation-filled voids are generated; these voids constitute 25% of the volume of the solid. Absorption isotherms for water show the completely reversible uptake of 4 to 5 percent by weight water into the micropores of this compound, which corresponds to 10 to 12 percent by volume.
November 18th, 2008 at 1:22 am
I think the answer is 3. I say “think” because I’m a freshman chemistry student myself and was googling the phrase “molybdenum(III) phosphate” looking for help on a similar question when I came across your question.
Here’s why I think it’s three:
The formula for the compound is Mo(PO4) because it’s Mo (III) and the charge of phosphate is a negative 3, so you don’t have to worry about any subscripts.
Which means that there is 1 atom of Mo in one formula, so in three formulas of it..there will be three.
Also:
I had the question “How many oxygen atoms are present in six formulas of the compond molybdenum(III) phosphate?” and the correct answer to that is 24, which makes sense using the method I explained above.
Let me know if this helps! Good Luck…