For 1.8 mole of the radioactive isotope molybdenum-99, half-life = 67 hours, how many disintegrations have occ
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henrick asked:
For 1.8 mole of the radioactive isotope molybdenum-99, half-life = 67 hours, how many disintegrations have occured after 17 minutes?
For 1.8 mole of the radioactive isotope molybdenum-99, half-life = 67 hours, how many disintegrations have occured after 17 minutes?
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November 11th, 2008 at 9:35 am
67 hours = 4020 minutes
17 minutes = 0.283 hours
ln 2 / 67 hrs = 0.0103/hr
N(.283) = 1.8 x e^ (-.0103 x .283)
= 1.8 x .9971
= 1.7947 moles remaining
1.8 mol - 1.7947 mol = 0.00522 moles
.00522 x (6.02e23) = 3.14e21