For 2.0 mole of the radioactive isotope molybdenum-99, half-life = 67 hours,?

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redhotstiletoes<3 asked:


how many disintegrations have occurred after 16 minutes?

Enter a numeric answer only do not include units

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One Response to “For 2.0 mole of the radioactive isotope molybdenum-99, half-life = 67 hours,?”

  1. shDowWonDeR Says:
    October 5th, 2008 at 1:53 am

    So use the formula
    Nt = No x e^-kt

    and we know that
    k= ln(2) / half life(which is t1/2)

    The quenstions given
    half life(t1/2) = 67 hr
    time(t) = 16min/ 60min/hr =0.2667hr
    the initial mole ( No) = 2.0 mole

    and then just plug in all the givens to above equation
    k = ln(2) / 67 hr
    = 0.0103454803 hr
    Nt = 2mol x e^ (0.0103454803hr x 0.2667hr)
    = 2.005525899

    and the last step is to multiply the avo’s number 6.022×10e23

    The final answer is 1.207928249E24

    hope it help!

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