What is the nuclear equation for the formation of molybdenum-99 from stable molybdenum-98 bombardeded with?

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Adam asked:


neutrons?

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This entry was posted on Friday, October 3rd, 2008 at 4:31 pm and is filed under Physics. You can follow any responses to this entry through the RSS 2.0 feed. You can leave a response, or trackback from your own site.

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For 2.0 mole of the radioactive isotope molybdenum-99, half-life = 67 hours,? »

One Response to “What is the nuclear equation for the formation of molybdenum-99 from stable molybdenum-98 bombardeded with?”

  1. Dr. J. Says:
    October 5th, 2008 at 3:53 am

    Here it is:

    (98,42)Mo + (1,0)n —> (99,42)Mo

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