Comments on: What is the nuclear equation for the formation of molybdenum-99 from stable molybdenum-98 bombardeded with neu http://molybdenuminfo.com/2008/08/14/what-is-the-nuclear-equation-for-the-formation-of-molybdenum-99-from-stable-molybdenum-98-bombardeded-with-neu/ Answering your molybdenum questions Sat, 11 Sep 2010 01:08:42 +0000 http://wordpress.org/?v=2.6.3 By: Dr. J. http://molybdenuminfo.com/2008/08/14/what-is-the-nuclear-equation-for-the-formation-of-molybdenum-99-from-stable-molybdenum-98-bombardeded-with-neu/#comment-44 Dr. J. Fri, 15 Aug 2008 14:28:55 +0000 http://molybdenuminfo.com/?p=48#comment-44 Here it is: (98,42)Mo + (1,0)n ---> (99,42)Mo Here it is:

(98,42)Mo + (1,0)n —> (99,42)Mo

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