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	<title>Comments on: For 1.3 mole of molybdenum-99, half-life 67 hours, how many disintegrations occured after 20 mins?</title>
	<atom:link href="http://molybdenuminfo.com/2008/06/10/for-13-mole-of-molybdenum-99-half-life-67-hours-how-many-disintegrations-occured-after-20-mins/feed/" rel="self" type="application/rss+xml" />
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	<description>Answering your molybdenum questions</description>
	<pubDate>Fri, 10 Sep 2010 23:03:56 +0000</pubDate>
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		<title>By: sarge_247</title>
		<link>http://molybdenuminfo.com/2008/06/10/for-13-mole-of-molybdenum-99-half-life-67-hours-how-many-disintegrations-occured-after-20-mins/#comment-63</link>
		<dc:creator>sarge_247</dc:creator>
		<pubDate>Fri, 13 Jun 2008 00:30:37 +0000</pubDate>
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		<description>A(t)=(1.3)(1-R)^t
67 hrs=4020 min
.65=1.3(1-R)^4020
.5=(1-R)^4020
R=1.724E-4

A(20)=1.3(1-1.724E-4)^20
A(20)=1.2955 mol= 7.799E23

1.3*6.02E23=7.826E23

7.826E23-7.799E23=2.7E21 atoms that disintegrate in 20 min</description>
		<content:encoded><![CDATA[<p>A(t)=(1.3)(1-R)^t<br />
67 hrs=4020 min<br />
.65=1.3(1-R)^4020<br />
.5=(1-R)^4020<br />
R=1.724E-4</p>
<p>A(20)=1.3(1-1.724E-4)^20<br />
A(20)=1.2955 mol= 7.799E23</p>
<p>1.3*6.02E23=7.826E23</p>
<p>7.826E23-7.799E23=2.7E21 atoms that disintegrate in 20 min</p>
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