For 1.3 mole of molybdenum-99, half-life 67 hours, how many disintegrations occured after 20 mins?

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trish asked:


For 1.3 mole of the radioactive isotope molybdenum-99, half-life = 67 hours, how many disintegrations have occurred after 20 minutes?

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One Response to “For 1.3 mole of molybdenum-99, half-life 67 hours, how many disintegrations occured after 20 mins?”

  1. sarge_247 Says:

    A(t)=(1.3)(1-R)^t
    67 hrs=4020 min
    .65=1.3(1-R)^4020
    .5=(1-R)^4020
    R=1.724E-4

    A(20)=1.3(1-1.724E-4)^20
    A(20)=1.2955 mol= 7.799E23

    1.3*6.02E23=7.826E23

    7.826E23-7.799E23=2.7E21 atoms that disintegrate in 20 min

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